Covering with latin transversals

Covering with latin transversals

0.00 Avg rating0 Votes
Article ID: iaor19961011
Country: Netherlands
Volume: 57
Issue: 1
Start Page Number: 1
End Page Number: 10
Publication Date: Feb 1995
Journal: Discrete Applied Mathematics
Authors: , ,
Abstract:

Given an n×n matrix A=[aij], a transversal of A is a set of elements, one from each row and one from each column. A transversal is a latin transversal if no two elements are the same. Erdös and Spencer showed that there always exists a latin transversal in any n×n matrix in which no element appears more than s times, for s•(n-1)/16. Here the authors show that, in fact, the elements of the matrix can be partitioned into n disjoint latin transversals, provided n is a power of 2 and no element appears more than •n times for some fixed •>0. The assumption that n is a power of 2 can be weakened, but at the moment we are unable to prove the theorem for all values of n.

Reviews

Required fields are marked *. Your email address will not be published.